(5x^2+3y^2-4)-(2x^2+3y^2-2)=

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Solution for (5x^2+3y^2-4)-(2x^2+3y^2-2)= equation:


Simplifying
(5x2 + 3y2 + -4) + -1(2x2 + 3y2 + -2) = 0

Reorder the terms:
(-4 + 5x2 + 3y2) + -1(2x2 + 3y2 + -2) = 0

Remove parenthesis around (-4 + 5x2 + 3y2)
-4 + 5x2 + 3y2 + -1(2x2 + 3y2 + -2) = 0

Reorder the terms:
-4 + 5x2 + 3y2 + -1(-2 + 2x2 + 3y2) = 0
-4 + 5x2 + 3y2 + (-2 * -1 + 2x2 * -1 + 3y2 * -1) = 0
-4 + 5x2 + 3y2 + (2 + -2x2 + -3y2) = 0

Reorder the terms:
-4 + 2 + 5x2 + -2x2 + 3y2 + -3y2 = 0

Combine like terms: -4 + 2 = -2
-2 + 5x2 + -2x2 + 3y2 + -3y2 = 0

Combine like terms: 5x2 + -2x2 = 3x2
-2 + 3x2 + 3y2 + -3y2 = 0

Combine like terms: 3y2 + -3y2 = 0
-2 + 3x2 + 0 = 0
-2 + 3x2 = 0

Solving
-2 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 3x2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 3x2 = 0 + 2
3x2 = 0 + 2

Combine like terms: 0 + 2 = 2
3x2 = 2

Divide each side by '3'.
x2 = 0.6666666667

Simplifying
x2 = 0.6666666667

Take the square root of each side:
x = {-0.816496581, 0.816496581}

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